\(11x^2+12x+1=0\) के मूल क्या होंगे?
What will be the roots of \(11x^2+12x+1=0\)?
Explanation opens after your attempt
Correct Answer
A. \(x=-\frac{1}{11},-1\)
Concept
((11x+1)(x+1)=0), so \(x=-\frac{1}{11}\) and (-1). In exams, ((11x+1)=0) gives \(-\frac{1}{11}\).
Why this answer is correct
The correct answer is A. \(x=-\frac{1}{11},-1\). ((11x+1)(x+1)=0), so \(x=-\frac{1}{11}\) and (-1). In exams, ((11x+1)=0) gives \(-\frac{1}{11}\).
Exam Tip
((11x+1)(x+1)=0), इसलिए \(x=-\frac{1}{11}\) और (-1) हैं। परीक्षा में ((11x+1)=0) से \(-\frac{1}{11}\) मिलता है।
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