Medium Mathematics Quadratic Equations Class 10 Level 35

\(3x^2+11x+10=0\) को हल करने पर मूल क्या होंगे?

What will be the roots after solving \(3x^2+11x+10=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=-2,-\frac{5}{3}\)

Step 1

Concept

(3x-2+11x+10=(3x+5)(x+2)), so the roots are \(-\frac{5}{3}\) and (-2). In exams, positive factors give negative roots.

Step 2

Why this answer is correct

The correct answer is A. \(x=-2,-\frac{5}{3}\). (3x-2+11x+10=(3x+5)(x+2)), so the roots are \(-\frac{5}{3}\) and (-2). In exams, positive factors give negative roots.

Step 3

Exam Tip

(3x-2+11x+10=(3x+5)(x+2)), इसलिए मूल \(-\frac{5}{3}\) और (-2) हैं। परीक्षा में धनात्मक गुणनखंडों से ऋणात्मक मूल मिलते हैं।

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Mathematics Answer, Explanation and Revision Hints

\(3x^2+11x+10=0\) को हल करने पर मूल क्या होंगे? / What will be the roots after solving \(3x^2+11x+10=0\)?

Correct Answer: A. \(x=-2,-\frac{5}{3}\). Explanation: (3x-2+11x+10=(3x+5)(x+2)), इसलिए मूल \(-\frac{5}{3}\) और (-2) हैं। परीक्षा में धनात्मक गुणनखंडों से ऋणात्मक मूल मिलते हैं। / (3x-2+11x+10=(3x+5)(x+2)), so the roots are \(-\frac{5}{3}\) and (-2). In exams, positive factors give negative roots.

Which concept should I revise for this Mathematics MCQ?

(3x-2+11x+10=(3x+5)(x+2)), so the roots are \(-\frac{5}{3}\) and (-2). In exams, positive factors give negative roots.

What exam hint can help solve this Mathematics question?

(3x-2+11x+10=(3x+5)(x+2)), इसलिए मूल \(-\frac{5}{3}\) और (-2) हैं। परीक्षा में धनात्मक गुणनखंडों से ऋणात्मक मूल मिलते हैं।

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