Medium Mathematics Quadratic Equations Class 10 Level 34

\(2x^2+7x+6=0\) को हल करने पर मूल क्या होंगे?

What will be the roots after solving \(2x^2+7x+6=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=-\frac{3}{2},-2\)

Step 1

Concept

(2x-2+7x+6=(2x+3)(x+2)), so \(x=-\frac{3}{2}\) and (-2). In exams, positive factors give negative roots.

Step 2

Why this answer is correct

The correct answer is A. \(x=-\frac{3}{2},-2\). (2x-2+7x+6=(2x+3)(x+2)), so \(x=-\frac{3}{2}\) and (-2). In exams, positive factors give negative roots.

Step 3

Exam Tip

(2x-2+7x+6=(2x+3)(x+2)), इसलिए \(x=-\frac{3}{2}\) और (-2) हैं। परीक्षा में धनात्मक गुणनखंडों से ऋणात्मक मूल मिलते हैं।

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Mathematics Answer, Explanation and Revision Hints

\(2x^2+7x+6=0\) को हल करने पर मूल क्या होंगे? / What will be the roots after solving \(2x^2+7x+6=0\)?

Correct Answer: A. \(x=-\frac{3}{2},-2\). Explanation: (2x-2+7x+6=(2x+3)(x+2)), इसलिए \(x=-\frac{3}{2}\) और (-2) हैं। परीक्षा में धनात्मक गुणनखंडों से ऋणात्मक मूल मिलते हैं। / (2x-2+7x+6=(2x+3)(x+2)), so \(x=-\frac{3}{2}\) and (-2). In exams, positive factors give negative roots.

Which concept should I revise for this Mathematics MCQ?

(2x-2+7x+6=(2x+3)(x+2)), so \(x=-\frac{3}{2}\) and (-2). In exams, positive factors give negative roots.

What exam hint can help solve this Mathematics question?

(2x-2+7x+6=(2x+3)(x+2)), इसलिए \(x=-\frac{3}{2}\) और (-2) हैं। परीक्षा में धनात्मक गुणनखंडों से ऋणात्मक मूल मिलते हैं।

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