\(x^2-6x-7=0\) के मूल पूर्ण वर्ग विधि से क्या होंगे?
What roots are obtained for \(x^2-6x-7=0\) by completing the square method?
Explanation opens after your attempt
Correct Answer
A. (x=7,-1)
Concept
Since ((x-3)2=16), \(x-3=\pm4\), so (x=7,-1). In exams, use \(\pm\) to find both roots.
Why this answer is correct
The correct answer is A. (x=7,-1). Since ((x-3)2=16), \(x-3=\pm4\), so (x=7,-1). In exams, use \(\pm\) to find both roots.
Exam Tip
((x-3)2=16), इसलिए \(x-3=\pm4\) और (x=7,-1) हैं। परीक्षा में \(\pm\) से दोनों मूल निकालें।
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