Expert Mathematics Quadratic Equations Class 10 Level 34

\(9x^2-30x+8=0\) के मूल पूर्ण वर्ग विधि से क्या होंगे?

What roots are obtained for \(9x^2-30x+8=0\) by completing square method?

Explanation opens after your attempt
Correct Answer

A. \(x=\frac{5\pm\sqrt{17}}{3}\)

Step 1

Concept

Since (\left\(x-\frac{5}{3}\right\)2=\frac{17}{9}), \(x=\frac{5\pm\sqrt{17}}{3}\). In exams, write the square root with the denominator correctly.

Step 2

Why this answer is correct

The correct answer is A. \(x=\frac{5\pm\sqrt{17}}{3}\). Since (\left\(x-\frac{5}{3}\right\)2=\frac{17}{9}), \(x=\frac{5\pm\sqrt{17}}{3}\). In exams, write the square root with the denominator correctly.

Step 3

Exam Tip

(\left\(x-\frac{5}{3}\right\)2=\frac{17}{9}), इसलिए \(x=\frac{5\pm\sqrt{17}}{3}\) है। परीक्षा में वर्गमूल को हर के साथ सही लिखें।

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Mathematics Answer, Explanation and Revision Hints

\(9x^2-30x+8=0\) के मूल पूर्ण वर्ग विधि से क्या होंगे? / What roots are obtained for \(9x^2-30x+8=0\) by completing square method?

Correct Answer: A. \(x=\frac{5\pm\sqrt{17}}{3}\). Explanation: (\left\(x-\frac{5}{3}\right\)2=\frac{17}{9}), इसलिए \(x=\frac{5\pm\sqrt{17}}{3}\) है। परीक्षा में वर्गमूल को हर के साथ सही लिखें। / Since (\left\(x-\frac{5}{3}\right\)2=\frac{17}{9}), \(x=\frac{5\pm\sqrt{17}}{3}\). In exams, write the square root with the denominator correctly.

Which concept should I revise for this Mathematics MCQ?

Since (\left\(x-\frac{5}{3}\right\)2=\frac{17}{9}), \(x=\frac{5\pm\sqrt{17}}{3}\). In exams, write the square root with the denominator correctly.

What exam hint can help solve this Mathematics question?

(\left\(x-\frac{5}{3}\right\)2=\frac{17}{9}), इसलिए \(x=\frac{5\pm\sqrt{17}}{3}\) है। परीक्षा में वर्गमूल को हर के साथ सही लिखें।

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