\(2x^2+8x+1=0\) के मूल पूर्ण वर्ग विधि से क्या होंगे?
What roots are obtained for \(2x^2+8x+1=0\) by completing the square method?
Explanation opens after your attempt
Correct Answer
A. \(x=-2\pm\frac{\sqrt{14}}{2}\)
Concept
Since ((x+2)2=\frac{7}{2}), \(x=-2\pm\sqrt{\frac{7}{2}}=-2\pm\frac{\sqrt{14}}{2}\). In exams, write the square root in simplified form.
Why this answer is correct
The correct answer is A. \(x=-2\pm\frac{\sqrt{14}}{2}\). Since ((x+2)2=\frac{7}{2}), \(x=-2\pm\sqrt{\frac{7}{2}}=-2\pm\frac{\sqrt{14}}{2}\). In exams, write the square root in simplified form.
Exam Tip
((x+2)2=\frac{7}{2}), इसलिए \(x=-2\pm\sqrt{\frac{7}{2}}=-2\pm\frac{\sqrt{14}}{2}\) है। परीक्षा में वर्गमूल को सरल रूप में लिखें।
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