\(11x^2-44x+7=0\) के मूल पूर्ण वर्ग विधि से क्या होंगे?
What roots are obtained for \(11x^2-44x+7=0\) by completing square method?
Explanation opens after your attempt
Correct Answer
A. \(x=2\pm\frac{\sqrt{407}}{11}\)
Concept
Since ((x-2)2=\frac{37}{11}), \(x=2\pm\sqrt{\frac{37}{11}}=2\pm\frac{\sqrt{407}}{11}\). In exams, rationalize the denominator.
Why this answer is correct
The correct answer is A. \(x=2\pm\frac{\sqrt{407}}{11}\). Since ((x-2)2=\frac{37}{11}), \(x=2\pm\sqrt{\frac{37}{11}}=2\pm\frac{\sqrt{407}}{11}\). In exams, rationalize the denominator.
Exam Tip
((x-2)2=\frac{37}{11}), इसलिए \(x=2\pm\sqrt{\frac{37}{11}}=2\pm\frac{\sqrt{407}}{11}\) है। परीक्षा में हर को परिमेय बनाएं।
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