\(12x^2+17x+5=0\) को गुणनखंड विधि से हल करने पर मूल क्या होंगे?
What roots are obtained by solving \(12x^2+17x+5=0\) by factorisation?
Explanation opens after your attempt
Correct Answer
A. \(x=-1,-\frac{5}{12}\)
Concept
(12x-2+17x+5=(12x+5)(x+1)), so the roots are \(-\frac{5}{12}\) and (-1). In exams, positive factors give negative roots.
Why this answer is correct
The correct answer is A. \(x=-1,-\frac{5}{12}\). (12x-2+17x+5=(12x+5)(x+1)), so the roots are \(-\frac{5}{12}\) and (-1). In exams, positive factors give negative roots.
Exam Tip
(12x-2+17x+5=(12x+5)(x+1)), इसलिए मूल \(-\frac{5}{12}\) और (-1) हैं। परीक्षा में धनात्मक गुणनखंडों से ऋणात्मक मूल मिलते हैं।
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