\(x^2-2\sqrt{17}x+17=0\) का मूल क्या है?
What is the root of \(x^2-2\sqrt{17}x+17=0\)?
Explanation opens after your attempt
Correct Answer
A. \(x=\sqrt{17}\)
Concept
(\(x-\sqrt{17}\)2=0), so the repeated root is \(\sqrt{17}\). In exams, ((x-a)2=0) gives (x=a).
Why this answer is correct
The correct answer is A. \(x=\sqrt{17}\). (\(x-\sqrt{17}\)2=0), so the repeated root is \(\sqrt{17}\). In exams, ((x-a)2=0) gives (x=a).
Exam Tip
(\(x-\sqrt{17}\)2=0), इसलिए दोहराया हुआ मूल \(\sqrt{17}\) है। परीक्षा में ((x-a)2=0) से (x=a) मिलता है।
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