Easy Mathematics Polynomials Class 10 Level 25

दो अपरिमेय संख्याओं का गुणनफल हमेशा कैसा होता है?

What is the product of two irrational numbers always?

Explanation opens after your attempt
Correct Answer

A. हमेशा निश्चित नहींNot always fixed

Step 1

Concept

\(\sqrt{2}\times\sqrt{2}=2\) is rational but \(\sqrt{2}\times\sqrt{3}=\sqrt{6}\) is irrational. So it is not always one type.

Step 2

Why this answer is correct

The correct answer is A. हमेशा निश्चित नहीं / Not always fixed. \(\sqrt{2}\times\sqrt{2}=2\) is rational but \(\sqrt{2}\times\sqrt{3}=\sqrt{6}\) is irrational. So it is not always one type.

Step 3

Exam Tip

\(\sqrt{2}\times\sqrt{2}=2\) परिमेय है लेकिन \(\sqrt{2}\times\sqrt{3}=\sqrt{6}\) अपरिमेय है। इसलिए हमेशा एक जैसा नहीं होता।

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Mathematics Answer, Explanation and Revision Hints

दो अपरिमेय संख्याओं का गुणनफल हमेशा कैसा होता है? / What is the product of two irrational numbers always?

Correct Answer: A. हमेशा निश्चित नहीं / Not always fixed. Explanation: \(\sqrt{2}\times\sqrt{2}=2\) परिमेय है लेकिन \(\sqrt{2}\times\sqrt{3}=\sqrt{6}\) अपरिमेय है। इसलिए हमेशा एक जैसा नहीं होता। / \(\sqrt{2}\times\sqrt{2}=2\) is rational but \(\sqrt{2}\times\sqrt{3}=\sqrt{6}\) is irrational. So it is not always one type.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{2}\times\sqrt{2}=2\) is rational but \(\sqrt{2}\times\sqrt{3}=\sqrt{6}\) is irrational. So it is not always one type.

What exam hint can help solve this Mathematics question?

\(\sqrt{2}\times\sqrt{2}=2\) परिमेय है लेकिन \(\sqrt{2}\times\sqrt{3}=\sqrt{6}\) अपरिमेय है। इसलिए हमेशा एक जैसा नहीं होता।

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