समीकरण \(x^2+14x+49=0\) में मूलों की प्रकृति क्या है?
What is the nature of roots of \(x^2+14x+49=0\)?
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Correct Answer
B. दो समान वास्तविक मूलTwo equal real roots
Concept
Here \(D=14^2-4\cdot1\cdot49=0\). Therefore the equation has two equal real roots.
Why this answer is correct
The correct answer is B. दो समान वास्तविक मूल / Two equal real roots. Here \(D=14^2-4\cdot1\cdot49=0\). Therefore the equation has two equal real roots.
Exam Tip
यहाँ \(D=14^2-4\cdot1\cdot49=0\) है। इसलिए इस समीकरण के दो समान वास्तविक मूल हैं।
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