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What is the discriminant of \(6x^2-5x+1=0\)?
A. (1)
(D=(-5)2-4(6)(1)=1). This gives two real and distinct roots.
The correct answer is A. (1). (D=(-5)2-4(6)(1)=1). This gives two real and distinct roots.
(D=(-5)2-4(6)(1)=1) है। इससे दो वास्तविक और असमान मूल होंगे।
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Correct Answer: A. (1). Explanation: (D=(-5)2-4(6)(1)=1) है। इससे दो वास्तविक और असमान मूल होंगे। / (D=(-5)2-4(6)(1)=1). This gives two real and distinct roots.
(D=(-5)2-4(6)(1)=1). This gives two real and distinct roots.
(D=(-5)2-4(6)(1)=1) है। इससे दो वास्तविक और असमान मूल होंगे।
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