(x-2-2(k+5)x+k-2=0) के समान मूलों के लिए (k) क्या होगा?
What is (k) for equal roots of (x-2-2(k+5)x+k-2=0)?
Explanation opens after your attempt
Correct Answer
A. \(k=-\frac{5}{2}\)
Concept
(D=4(k+5)2-4k-2=0) gives ((k+5)2=k-2), so (10k+25=0) and \(k=-\frac{5}{2}\). In exams, expand squares carefully.
Why this answer is correct
The correct answer is A. \(k=-\frac{5}{2}\). (D=4(k+5)2-4k-2=0) gives ((k+5)2=k-2), so (10k+25=0) and \(k=-\frac{5}{2}\). In exams, expand squares carefully.
Exam Tip
(D=4(k+5)2-4k-2=0) से ((k+5)2=k-2), इसलिए (10k+25=0) और \(k=-\frac{5}{2}\) है। परीक्षा में वर्ग फैलाते समय सावधानी रखें।
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