By the half-angle identity, \(\frac{\sin x}{1-\cos x}=\cot \frac{x}{2}\). In such forms, identify the denominator carefully.
Step 2
Why this answer is correct
The correct answer is B. \(\cot \frac{x}{2}\). By the half-angle identity, \(\frac{\sin x}{1-\cos x}=\cot \frac{x}{2}\). In such forms, identify the denominator carefully.
Step 3
Exam Tip
अर्ध-कोण पहचान से \(\frac{\sin x}{1-\cos x}=\cot \frac{x}{2}\) होता है। ऐसे रूपों में हर देखकर पहचान करें।
Mathematics Answer, Explanation and Revision Hints
\(\frac{\sin x}{1-\cos x}\) किसके बराबर है? / What is \(\frac{\sin x}{1-\cos x}\) equal to?
Correct Answer: B. \(\cot \frac{x}{2}\). Explanation: अर्ध-कोण पहचान से \(\frac{\sin x}{1-\cos x}=\cot \frac{x}{2}\) होता है। ऐसे रूपों में हर देखकर पहचान करें। / By the half-angle identity, \(\frac{\sin x}{1-\cos x}=\cot \frac{x}{2}\). In such forms, identify the denominator carefully.
Which concept should I revise for this Mathematics MCQ?
By the half-angle identity, \(\frac{\sin x}{1-\cos x}=\cot \frac{x}{2}\). In such forms, identify the denominator carefully.
What exam hint can help solve this Mathematics question?
अर्ध-कोण पहचान से \(\frac{\sin x}{1-\cos x}=\cot \frac{x}{2}\) होता है। ऐसे रूपों में हर देखकर पहचान करें।
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