\(x^2+6x+2=0\) के मूल क्या हैं?
What are the roots of \(x^2+6x+2=0\)?
Explanation opens after your attempt
Correct Answer
A. \(x=-3\pm\sqrt{7}\)
Concept
Since ((x+3)2=7), \(x=-3\pm\sqrt{7}\). In exams, write both values using \(\pm\).
Why this answer is correct
The correct answer is A. \(x=-3\pm\sqrt{7}\). Since ((x+3)2=7), \(x=-3\pm\sqrt{7}\). In exams, write both values using \(\pm\).
Exam Tip
((x+3)2=7), इसलिए \(x=-3\pm\sqrt{7}\) है। परीक्षा में \(\pm\) के दोनों मान लिखें।
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