\(x^2+6x+1=0\) के मूल पूर्ण वर्ग विधि से क्या होंगे?
What are the roots of \(x^2+6x+1=0\) by completing the square method?
Explanation opens after your attempt
Correct Answer
A. \(x=-3\pm2\sqrt{2}\)
Concept
Since ((x+3)2=8), \(x=-3\pm2\sqrt{2}\). In exams, simplify \(\sqrt{8}=2\sqrt{2}\).
Why this answer is correct
The correct answer is A. \(x=-3\pm2\sqrt{2}\). Since ((x+3)2=8), \(x=-3\pm2\sqrt{2}\). In exams, simplify \(\sqrt{8}=2\sqrt{2}\).
Exam Tip
((x+3)2=8), इसलिए \(x=-3\pm2\sqrt{2}\) है। परीक्षा में \(\sqrt{8}=2\sqrt{2}\) सरल करें।
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