\(x^2+4x-12=0\) के मूल क्या हैं?
What are the roots of \(x^2+4x-12=0\)?
Explanation opens after your attempt
A. (x=2,-6)
Concept
Since ((x+2)2=16), \(x+2=\pm4\), so (x=2,-6). In exams, use \(\pm\) to get both answers.
Why this answer is correct
The correct answer is A. (x=2,-6). Since ((x+2)2=16), \(x+2=\pm4\), so (x=2,-6). In exams, use \(\pm\) to get both answers.
Exam Tip
((x+2)2=16), इसलिए \(x+2=\pm4\) और (x=2,-6) हैं। परीक्षा में \(\pm\) से दोनों उत्तर निकालें।
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