\(x^2-16x+28=0\) के मूल क्या हैं?
What are the roots of \(x^2-16x+28=0\)?
Explanation opens after your attempt
Correct Answer
A. (x=2,14)
Concept
Since ((x-8)2=36), \(x-8=\pm6\), so (x=2,14). In exams, use \(\pm\) to find both roots.
Why this answer is correct
The correct answer is A. (x=2,14). Since ((x-8)2=36), \(x-8=\pm6\), so (x=2,14). In exams, use \(\pm\) to find both roots.
Exam Tip
((x-8)2=36), इसलिए \(x-8=\pm6\) और (x=2,14) हैं। परीक्षा में \(\pm\) से दोनों मूल निकालें।
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