\(x^2+12x+8=0\) के मूल क्या हैं?
What are the roots of \(x^2+12x+8=0\)?
Explanation opens after your attempt
Correct Answer
A. \(x=-6\pm2\sqrt{7}\)
Concept
Since ((x+6)2=28), \(x=-6\pm2\sqrt{7}\). In exams, simplify \(\sqrt{28}=2\sqrt{7}\).
Why this answer is correct
The correct answer is A. \(x=-6\pm2\sqrt{7}\). Since ((x+6)2=28), \(x=-6\pm2\sqrt{7}\). In exams, simplify \(\sqrt{28}=2\sqrt{7}\).
Exam Tip
((x+6)2=28), इसलिए \(x=-6\pm2\sqrt{7}\) है। परीक्षा में \(\sqrt{28}=2\sqrt{7}\) सरल करें।
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