\(x^2-12x+20=0\) के मूल क्या हैं?
What are the roots of \(x^2-12x+20=0\)?
Explanation opens after your attempt
A. (x=2,10)
Concept
Since ((x-6)2=16), \(x-6=\pm4\), so (x=2,10). In exams, take both values from \(\pm\).
Why this answer is correct
The correct answer is A. (x=2,10). Since ((x-6)2=16), \(x-6=\pm4\), so (x=2,10). In exams, take both values from \(\pm\).
Exam Tip
((x-6)2=16), इसलिए \(x-6=\pm4\) और (x=2,10) हैं। परीक्षा में \(\pm\) के दोनों मान लें।
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