Expert Mathematics Quadratic Equations Class 10 Level 36

\(8x^2-14x-15=0\) के मूल क्या हैं?

What are the roots of \(8x^2-14x-15=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\frac{5}{2},-\frac{3}{4}\)

Step 1

Concept

((4x+3)(2x-5)=0), so \(x=-\frac{3}{4}\) and \(\frac{5}{2}\). In exams, change signs while writing roots.

Step 2

Why this answer is correct

The correct answer is A. \(x=\frac{5}{2},-\frac{3}{4}\). ((4x+3)(2x-5)=0), so \(x=-\frac{3}{4}\) and \(\frac{5}{2}\). In exams, change signs while writing roots.

Step 3

Exam Tip

((4x+3)(2x-5)=0), इसलिए \(x=-\frac{3}{4}\) और \(\frac{5}{2}\) हैं। परीक्षा में संकेत बदलकर मूल लिखें।

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Mathematics Answer, Explanation and Revision Hints

\(8x^2-14x-15=0\) के मूल क्या हैं? / What are the roots of \(8x^2-14x-15=0\)?

Correct Answer: A. \(x=\frac{5}{2},-\frac{3}{4}\). Explanation: ((4x+3)(2x-5)=0), इसलिए \(x=-\frac{3}{4}\) और \(\frac{5}{2}\) हैं। परीक्षा में संकेत बदलकर मूल लिखें। / ((4x+3)(2x-5)=0), so \(x=-\frac{3}{4}\) and \(\frac{5}{2}\). In exams, change signs while writing roots.

Which concept should I revise for this Mathematics MCQ?

((4x+3)(2x-5)=0), so \(x=-\frac{3}{4}\) and \(\frac{5}{2}\). In exams, change signs while writing roots.

What exam hint can help solve this Mathematics question?

((4x+3)(2x-5)=0), इसलिए \(x=-\frac{3}{4}\) और \(\frac{5}{2}\) हैं। परीक्षा में संकेत बदलकर मूल लिखें।

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