Easy Mathematics Quadratic Equations Class 10 Level 36

\(16x^2-25=0\) के मूल क्या हैं?

What are the roots of \(16x^2-25=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\frac{5}{4},-\frac{5}{4}\)

Step 1

Concept

((4x-5)(4x+5)=0), so \(x=\frac{5}{4}\) or \(x=-\frac{5}{4}\). In exams, solve linear factors carefully.

Step 2

Why this answer is correct

The correct answer is A. \(x=\frac{5}{4},-\frac{5}{4}\). ((4x-5)(4x+5)=0), so \(x=\frac{5}{4}\) or \(x=-\frac{5}{4}\). In exams, solve linear factors carefully.

Step 3

Exam Tip

((4x-5)(4x+5)=0), इसलिए \(x=\frac{5}{4}\) या \(x=-\frac{5}{4}\) है। परीक्षा में रैखिक गुणनखंड सावधानी से हल करें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(16x^2-25=0\) के मूल क्या हैं? / What are the roots of \(16x^2-25=0\)?

Correct Answer: A. \(x=\frac{5}{4},-\frac{5}{4}\). Explanation: ((4x-5)(4x+5)=0), इसलिए \(x=\frac{5}{4}\) या \(x=-\frac{5}{4}\) है। परीक्षा में रैखिक गुणनखंड सावधानी से हल करें। / ((4x-5)(4x+5)=0), so \(x=\frac{5}{4}\) or \(x=-\frac{5}{4}\). In exams, solve linear factors carefully.

Which concept should I revise for this Mathematics MCQ?

((4x-5)(4x+5)=0), so \(x=\frac{5}{4}\) or \(x=-\frac{5}{4}\). In exams, solve linear factors carefully.

What exam hint can help solve this Mathematics question?

((4x-5)(4x+5)=0), इसलिए \(x=\frac{5}{4}\) या \(x=-\frac{5}{4}\) है। परीक्षा में रैखिक गुणनखंड सावधानी से हल करें।

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