गुणनखंड विधि से \(4x^2-12x+5=0\) के मूल क्या होंगे?
Using factorisation method, what will be the roots of \(4x^2-12x+5=0\)?
Explanation opens after your attempt
Correct Answer
A. \(x=\frac{1}{2},\frac{5}{2}\)
Concept
(4x-2-12x+5=(2x-1)(2x-5)), so the roots are \(\frac{1}{2}\) and \(\frac{5}{2}\). In exams, solve each linear factor separately.
Why this answer is correct
The correct answer is A. \(x=\frac{1}{2},\frac{5}{2}\). (4x-2-12x+5=(2x-1)(2x-5)), so the roots are \(\frac{1}{2}\) and \(\frac{5}{2}\). In exams, solve each linear factor separately.
Exam Tip
(4x-2-12x+5=(2x-1)(2x-5)), इसलिए मूल \(\frac{1}{2}\) और \(\frac{5}{2}\) हैं। परीक्षा में हर रैखिक गुणनखंड को अलग हल करें।
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