Home
Subjects
If (x+y+z=10) and (xy+yz+zx=28), what is (x power... |...
यदि (x+y+z=10) और (xy+yz+zx=28) हो तो \(x^2+y^2+z^2\) क्या है?
If (x+y+z=10) and (xy+yz+zx=28), what is \(x^2+y^2+z^2\)?
#three term identity
#given values
#sum of squares
A (44) / सही मान
B (100) / केवल योग का वर्ग
C (56) / केवल दोहरा गुणन
D (72) / घटाव गलत
Explanation opens after your attempt
Correct Answer
A. (44) / सही मान
Step 1
Concept
(100=x-2 +y-2 +z-2 +2(28)). Therefore \(x^2+y^2+z^2=44\).
Step 2
Why this answer is correct
The correct answer is A. (44) / सही मान. (100=x-2 +y-2 +z-2 +2(28)). Therefore \(x^2+y^2+z^2=44\).
Step 3
Exam Tip
(100=x-2 +y-2 +z-2 +2(28)) है। इसलिए \(x^2+y^2+z^2=44\) मिलता है।
Login to save your score, XP, coins and progress. Login
Question me issue ya doubt hai?
Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365
Login karke aap is question ka doubt, correction ya suggestion bhej sakte hain aur reply track kar sakte hain.
Related Mathematics Questions
Related Mathematics Learning Links
FAQs
Mathematics Answer, Explanation and Revision Hints
यदि (x+y+z=10) और (xy+yz+zx=28) हो तो \(x^2+y^2+z^2\) क्या है? / If (x+y+z=10) and (xy+yz+zx=28), what is \(x^2+y^2+z^2\)?
Correct Answer: A. (44) / सही मान. Explanation: (100=x-2 +y-2 +z-2 +2(28)) है। इसलिए \(x^2+y^2+z^2=44\) मिलता है। / (100=x-2 +y-2 +z-2 +2(28)). Therefore \(x^2+y^2+z^2=44\).
Which concept should I revise for this Mathematics MCQ?
(100=x-2 +y-2 +z-2 +2(28)). Therefore \(x^2+y^2+z^2=44\).
What exam hint can help solve this Mathematics question?
(100=x-2 +y-2 +z-2 +2(28)) है। इसलिए \(x^2+y^2+z^2=44\) मिलता है।
Student Class Required
Select your class first
Quiz questions, daily challenge and practice pages will open according to your selected class. Class 11/12 ke liye stream bhi select karein.
