यदि ( (x+y)2=81 ) और (xy=14) है तो \(x^2+y^2\) का मान क्या होगा?

If ( (x+y)2=81 ) and (xy=14), what is the value of \(x^2+y^2\)?

Explanation opens after your attempt
Correct Answer

A. (53)

Step 1

Concept

(x-2+y-2=(x+y)2-2xy=81-28=53). Exam tip: subtract (2xy) from the square of the sum.

Step 2

Why this answer is correct

The correct answer is A. (53). (x-2+y-2=(x+y)2-2xy=81-28=53). Exam tip: subtract (2xy) from the square of the sum.

Step 3

Exam Tip

(x-2+y-2=(x+y)2-2xy=81-28=53) है। परीक्षा में वर्ग योग से (2xy) घटाएँ।

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Mathematics Answer, Explanation and Revision Hints

यदि ( (x+y)2=81 ) और (xy=14) है तो \(x^2+y^2\) का मान क्या होगा? / If ( (x+y)2=81 ) and (xy=14), what is the value of \(x^2+y^2\)?

Correct Answer: A. (53). Explanation: (x-2+y-2=(x+y)2-2xy=81-28=53) है। परीक्षा में वर्ग योग से (2xy) घटाएँ। / (x-2+y-2=(x+y)2-2xy=81-28=53). Exam tip: subtract (2xy) from the square of the sum.

Which concept should I revise for this Mathematics MCQ?

(x-2+y-2=(x+y)2-2xy=81-28=53). Exam tip: subtract (2xy) from the square of the sum.

What exam hint can help solve this Mathematics question?

(x-2+y-2=(x+y)2-2xy=81-28=53) है। परीक्षा में वर्ग योग से (2xy) घटाएँ।

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