Expert Mathematics Polynomials Class 10 Level 27

यदि \(x=\sqrt{8}-\sqrt{2}\), तो (x) किसके बराबर है?

If \(x=\sqrt{8}-\sqrt{2}\), what is (x) equal to?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{2}\)

Step 1

Concept

\(\sqrt{8}=2\sqrt{2}\), so \(\sqrt{8}-\sqrt{2}=\sqrt{2}\). In exams simplify radicals first.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{2}\). \(\sqrt{8}=2\sqrt{2}\), so \(\sqrt{8}-\sqrt{2}=\sqrt{2}\). In exams simplify radicals first.

Step 3

Exam Tip

\(\sqrt{8}=2\sqrt{2}\), इसलिए \(\sqrt{8}-\sqrt{2}=\sqrt{2}\) है। परीक्षा में पहले मूलों को सरल करें।

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(x=\sqrt{8}-\sqrt{2}\), तो (x) किसके बराबर है? / If \(x=\sqrt{8}-\sqrt{2}\), what is (x) equal to?

Correct Answer: A. \(\sqrt{2}\). Explanation: \(\sqrt{8}=2\sqrt{2}\), इसलिए \(\sqrt{8}-\sqrt{2}=\sqrt{2}\) है। परीक्षा में पहले मूलों को सरल करें। / \(\sqrt{8}=2\sqrt{2}\), so \(\sqrt{8}-\sqrt{2}=\sqrt{2}\). In exams simplify radicals first.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{8}=2\sqrt{2}\), so \(\sqrt{8}-\sqrt{2}=\sqrt{2}\). In exams simplify radicals first.

What exam hint can help solve this Mathematics question?

\(\sqrt{8}=2\sqrt{2}\), इसलिए \(\sqrt{8}-\sqrt{2}=\sqrt{2}\) है। परीक्षा में पहले मूलों को सरल करें।

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