Expert Mathematics Polynomials Class 10 Level 27

यदि \(x=\sqrt{6}+\sqrt{5}\) और \(y=\sqrt{6}-\sqrt{5}\), तो \(x^2-y^2\) क्या है?

If \(x=\sqrt{6}+\sqrt{5}\) and \(y=\sqrt{6}-\sqrt{5}\), what is \(x^2-y^2\)?

Explanation opens after your attempt
Correct Answer

A. \(4\sqrt{30}\)

Step 1

Concept

(x-2-y-2=(x-y)(x+y)=\(2\sqrt{5}\)\(2\sqrt{6}\)=4\sqrt{30}). In exams identities save long calculations.

Step 2

Why this answer is correct

The correct answer is A. \(4\sqrt{30}\). (x-2-y-2=(x-y)(x+y)=\(2\sqrt{5}\)\(2\sqrt{6}\)=4\sqrt{30}). In exams identities save long calculations.

Step 3

Exam Tip

(x-2-y-2=(x-y)(x+y)=\(2\sqrt{5}\)\(2\sqrt{6}\)=4\sqrt{30}) है। परीक्षा में पहचान से लंबी गणना बचती है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(x=\sqrt{6}+\sqrt{5}\) और \(y=\sqrt{6}-\sqrt{5}\), तो \(x^2-y^2\) क्या है? / If \(x=\sqrt{6}+\sqrt{5}\) and \(y=\sqrt{6}-\sqrt{5}\), what is \(x^2-y^2\)?

Correct Answer: A. \(4\sqrt{30}\). Explanation: (x-2-y-2=(x-y)(x+y)=\(2\sqrt{5}\)\(2\sqrt{6}\)=4\sqrt{30}) है। परीक्षा में पहचान से लंबी गणना बचती है। / (x-2-y-2=(x-y)(x+y)=\(2\sqrt{5}\)\(2\sqrt{6}\)=4\sqrt{30}). In exams identities save long calculations.

Which concept should I revise for this Mathematics MCQ?

(x-2-y-2=(x-y)(x+y)=\(2\sqrt{5}\)\(2\sqrt{6}\)=4\sqrt{30}). In exams identities save long calculations.

What exam hint can help solve this Mathematics question?

(x-2-y-2=(x-y)(x+y)=\(2\sqrt{5}\)\(2\sqrt{6}\)=4\sqrt{30}) है। परीक्षा में पहचान से लंबी गणना बचती है।

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