यदि \(x=\sqrt{5}+\sqrt{3}\), तो \(x^2\) किस प्रकार की संख्या है?
If \(x=\sqrt{5}+\sqrt{3}\), then what type of number is \(x^2\)?
Explanation opens after your attempt
Correct Answer
A. \(8+2\sqrt{15}\), अपरिमेय\(8+2\sqrt{15}\), irrational
Concept
\(x^2=5+3+2\sqrt{15}=8+2\sqrt{15}\), so it is irrational. In exams use ((a+b)2) carefully.
Why this answer is correct
The correct answer is A. \(8+2\sqrt{15}\), अपरिमेय / \(8+2\sqrt{15}\), irrational. \(x^2=5+3+2\sqrt{15}=8+2\sqrt{15}\), so it is irrational. In exams use ((a+b)2) carefully.
Exam Tip
\(x^2=5+3+2\sqrt{15}=8+2\sqrt{15}\), इसलिए यह अपरिमेय है। परीक्षा में ((a+b)2) का प्रयोग सावधानी से करें।
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