Hard Mathematics Polynomials Class 10 Level 25

यदि \(x=2+\sqrt{3}\) है तो कौन सा समीकरण सत्य है?

If \(x=2+\sqrt{3}\), which equation is true?

Explanation opens after your attempt
Correct Answer

A. \(x^2-4x+1=0\)

Step 1

Concept

The conjugate is \(2-\sqrt{3}\), with sum (4) and product (1). Hence the equation is \(x^2-4x+1=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-4x+1=0\). The conjugate is \(2-\sqrt{3}\), with sum (4) and product (1). Hence the equation is \(x^2-4x+1=0\).

Step 3

Exam Tip

(x) का संयुग्मी \(2-\sqrt{3}\) है और योग (4), गुणनफल (1) है। इसलिए समीकरण \(x^2-4x+1=0\) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(x=2+\sqrt{3}\) है तो कौन सा समीकरण सत्य है? / If \(x=2+\sqrt{3}\), which equation is true?

Correct Answer: A. \(x^2-4x+1=0\). Explanation: (x) का संयुग्मी \(2-\sqrt{3}\) है और योग (4), गुणनफल (1) है। इसलिए समीकरण \(x^2-4x+1=0\) है। / The conjugate is \(2-\sqrt{3}\), with sum (4) and product (1). Hence the equation is \(x^2-4x+1=0\).

Which concept should I revise for this Mathematics MCQ?

The conjugate is \(2-\sqrt{3}\), with sum (4) and product (1). Hence the equation is \(x^2-4x+1=0\).

What exam hint can help solve this Mathematics question?

(x) का संयुग्मी \(2-\sqrt{3}\) है और योग (4), गुणनफल (1) है। इसलिए समीकरण \(x^2-4x+1=0\) है।

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