यदि (x-2+(m-2)x+25=0) की जड़ें समान हैं, तो (m) के मान क्या हैं?
If (x-2+(m-2)x+25=0) has equal roots, what are the values of (m)?
Explanation opens after your attempt
A. (12) और (-8)(12) and (-8)
Concept
For equal roots, ((m-2)2-100=0). Thus \(m-2=\pm10\), so (m=12) or (m=-8).
Why this answer is correct
The correct answer is A. (12) और (-8) / (12) and (-8). For equal roots, ((m-2)2-100=0). Thus \(m-2=\pm10\), so (m=12) or (m=-8).
Exam Tip
समान जड़ों के लिए ((m-2)2-100=0) होगा। इसलिए \(m-2=\pm10\), अतः (m=12) या (m=-8)।
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