Medium Mathematics Quadratic Equations Class 10 Level 36

यदि \(x^2-24x+108=0\) को पूर्ण वर्ग विधि से हल किया जाए, तो सही मध्य चरण कौनसा है?

If \(x^2-24x+108=0\) is solved by completing the square, which middle step is correct?

Explanation opens after your attempt
Correct Answer

A. ((x-12)2=36)

Step 1

Concept

Adding (144) to \(x^2-24x=-108\) gives ((x-12)2=36). In exams, add the square of half the coefficient to both sides.

Step 2

Why this answer is correct

The correct answer is A. ((x-12)2=36). Adding (144) to \(x^2-24x=-108\) gives ((x-12)2=36). In exams, add the square of half the coefficient to both sides.

Step 3

Exam Tip

\(x^2-24x=-108\) में (144) जोड़ने पर ((x-12)2=36) मिलता है। परीक्षा में आधे गुणांक का वर्ग दोनों पक्षों में जोड़ें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2-24x+108=0\) को पूर्ण वर्ग विधि से हल किया जाए, तो सही मध्य चरण कौनसा है? / If \(x^2-24x+108=0\) is solved by completing the square, which middle step is correct?

Correct Answer: A. ((x-12)2=36). Explanation: \(x^2-24x=-108\) में (144) जोड़ने पर ((x-12)2=36) मिलता है। परीक्षा में आधे गुणांक का वर्ग दोनों पक्षों में जोड़ें। / Adding (144) to \(x^2-24x=-108\) gives ((x-12)2=36). In exams, add the square of half the coefficient to both sides.

Which concept should I revise for this Mathematics MCQ?

Adding (144) to \(x^2-24x=-108\) gives ((x-12)2=36). In exams, add the square of half the coefficient to both sides.

What exam hint can help solve this Mathematics question?

\(x^2-24x=-108\) में (144) जोड़ने पर ((x-12)2=36) मिलता है। परीक्षा में आधे गुणांक का वर्ग दोनों पक्षों में जोड़ें।

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