यदि (x-2-2(k-5)x+k-2-36=0) के मूल समान हों, तो (k) का मान क्या होगा?
If (x-2-2(k-5)x+k-2-36=0) has equal roots, what is the value of (k)?
Explanation opens after your attempt
Correct Answer
A. \(k=\frac{61}{10}\)
Concept
For equal roots, (D=0), so ((k-5)2=k-2-36) and \(k=\frac{61}{10}\). In exams, handle constant terms carefully while expanding squares.
Why this answer is correct
The correct answer is A. \(k=\frac{61}{10}\). For equal roots, (D=0), so ((k-5)2=k-2-36) and \(k=\frac{61}{10}\). In exams, handle constant terms carefully while expanding squares.
Exam Tip
समान मूलों के लिए (D=0), इसलिए ((k-5)2=k-2-36) और \(k=\frac{61}{10}\) है। परीक्षा में वर्ग फैलाते समय स्थिर पद ध्यान से लें।
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