यदि (x-2-2(k+3)x+k-2-16=0) के मूल समान हों, तो (k) का मान क्या होगा?
If (x-2-2(k+3)x+k-2-16=0) has equal roots, what is the value of (k)?
Explanation opens after your attempt
Correct Answer
A. \(k=\frac{7}{6}\)
Concept
For equal roots, (D=0), so (4(k+3)2-4\(k^2-16\)=0) must be expanded carefully; a wrong expansion changes the answer. In exams, recheck parameter expansion.
Why this answer is correct
The correct answer is A. \(k=\frac{7}{6}\). For equal roots, (D=0), so (4(k+3)2-4\(k^2-16\)=0) must be expanded carefully; a wrong expansion changes the answer. In exams, recheck parameter expansion.
Exam Tip
समान मूलों के लिए (D=0), इसलिए (4(k+3)2-4\(k^2-16\)=0) से (6k+25=0) नहीं बल्कि (6k+25) गलत होगा; सही फैलाने पर (6k+25) नहीं बनता। परीक्षा में विस्तार दोबारा जांचें।
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