यदि (x-2-2(k+2)x+k-2+5=0) की जड़ें समान हैं, तो (k) का मान क्या होगा?
If (x-2-2(k+2)x+k-2+5=0) has equal roots, what is the value of (k)?
Explanation opens after your attempt
Correct Answer
A. \(\frac{1}{4}\)
Concept
For equal roots, put (D=0). Simplifying (4(k+2)2-4\(k^2+5\)=0) gives (4k-1=0), so \(k=\frac{1}{4}\).
Why this answer is correct
The correct answer is A. \(\frac{1}{4}\). For equal roots, put (D=0). Simplifying (4(k+2)2-4\(k^2+5\)=0) gives (4k-1=0), so \(k=\frac{1}{4}\).
Exam Tip
समान जड़ों के लिए (D=0) रखें। (4(k+2)2-4\(k^2+5\)=0) से (4k+3=0) नहीं, बल्कि (4k-1=0) नहीं; सही सरलीकरण (4k-1=0) देता है, इसलिए \(k=\frac{1}{4}\)।
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