यदि \(x=1+\sqrt{2}\), तो \(x+\frac{1}{x}\) का मान क्या है?
If \(x=1+\sqrt{2}\), what is \(x+\frac{1}{x}\)?
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{2}\)
Concept
\(\frac{1}{1+\sqrt{2}}=\sqrt{2}-1\), so the sum is \(2\sqrt{2}\). Rationalising the denominator is a quick exam method.
Why this answer is correct
The correct answer is A. \(2\sqrt{2}\). \(\frac{1}{1+\sqrt{2}}=\sqrt{2}-1\), so the sum is \(2\sqrt{2}\). Rationalising the denominator is a quick exam method.
Exam Tip
\(\frac{1}{1+\sqrt{2}}=\sqrt{2}-1\), इसलिए योग \(2\sqrt{2}\) है। परीक्षा में हर का परिमेयकरण तेज तरीका है।
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