यदि (p(x)=x-2-kx+1) के शून्यक \(2+\sqrt{3}\) और \(2-\sqrt{3}\) हैं, तो (k) का मान क्या है?
If the zeroes of (p(x)=x-2-kx+1) are \(2+\sqrt{3}\) and \(2-\sqrt{3}\), what is the value of (k)?
Explanation opens after your attempt
B. (4)
Concept
The sum of zeroes is (4), and in \(x^2-kx+1\), the sum is (k). Hence (k=4).
Why this answer is correct
The correct answer is B. (4). The sum of zeroes is (4), and in \(x^2-kx+1\), the sum is (k). Hence (k=4).
Exam Tip
शून्यकों का योग (4) है और \(x^2-kx+1\) में योग (k) होता है। इसलिए (k=4) है।
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