यदि \(8x^2+px+32=0\) के मूलों का योग (-9) है, तो (p) क्या होगा?
If the sum of roots of \(8x^2+px+32=0\) is (-9), what is (p)?
Explanation opens after your attempt
Correct Answer
A. (72)
Step 1
Concept
The sum of roots is \(-\frac{p}{8}\), so \(-\frac{p}{8}=-9\) gives (p=72). In exams, remember the sum formula \(-\frac{b}{a}\).
Step 2
Why this answer is correct
The correct answer is A. (72). The sum of roots is \(-\frac{p}{8}\), so \(-\frac{p}{8}=-9\) gives (p=72). In exams, remember the sum formula \(-\frac{b}{a}\).
Step 3
Exam Tip
मूलों का योग \(-\frac{p}{8}\) है, इसलिए \(-\frac{p}{8}=-9\) से (p=72) है। परीक्षा में योग का सूत्र \(-\frac{b}{a}\) याद रखें।
Mathematics Answer, Explanation and Revision Hints
यदि \(8x^2+px+32=0\) के मूलों का योग (-9) है, तो (p) क्या होगा? / If the sum of roots of \(8x^2+px+32=0\) is (-9), what is (p)?
Correct Answer: A. (72). Explanation: मूलों का योग \(-\frac{p}{8}\) है, इसलिए \(-\frac{p}{8}=-9\) से (p=72) है। परीक्षा में योग का सूत्र \(-\frac{b}{a}\) याद रखें। / The sum of roots is \(-\frac{p}{8}\), so \(-\frac{p}{8}=-9\) gives (p=72). In exams, remember the sum formula \(-\frac{b}{a}\).
Which concept should I revise for this Mathematics MCQ?
The sum of roots is \(-\frac{p}{8}\), so \(-\frac{p}{8}=-9\) gives (p=72). In exams, remember the sum formula \(-\frac{b}{a}\).
What exam hint can help solve this Mathematics question?
मूलों का योग \(-\frac{p}{8}\) है, इसलिए \(-\frac{p}{8}=-9\) से (p=72) है। परीक्षा में योग का सूत्र \(-\frac{b}{a}\) याद रखें।
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