यदि \(x^2-2mx+64=0\) के मूल समान हैं, तो (m) के संभावित मान क्या हैं?
If the roots of \(x^2-2mx+64=0\) are equal, what are the possible values of (m)?
Explanation opens after your attempt
Correct Answer
A. \(m=\pm8\)
Concept
For equal roots, (D=0) is needed. Here ((-2m)2-256=0), so \(m=\pm8\).
Why this answer is correct
The correct answer is A. \(m=\pm8\). For equal roots, (D=0) is needed. Here ((-2m)2-256=0), so \(m=\pm8\).
Exam Tip
समान मूलों के लिए (D=0) चाहिए। यहाँ ((-2m)2-256=0), इसलिए \(m=\pm8\)।
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