Expert Mathematics Quadratic Equations Class 10 Level 29

यदि \(x^2-2mx+49=0\) के मूल समान हैं, तो (m) के संभावित मान क्या हैं?

If the roots of \(x^2-2mx+49=0\) are equal, what are the possible values of (m)?

Explanation opens after your attempt
Correct Answer

A. \(m=\pm7\)

Step 1

Concept

For equal roots, (D=0) is needed. Here ((-2m)2-196=0), so \(m=\pm7\).

Step 2

Why this answer is correct

The correct answer is A. \(m=\pm7\). For equal roots, (D=0) is needed. Here ((-2m)2-196=0), so \(m=\pm7\).

Step 3

Exam Tip

समान मूलों के लिए (D=0) चाहिए। यहाँ ((-2m)2-196=0), इसलिए \(m=\pm7\)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2-2mx+49=0\) के मूल समान हैं, तो (m) के संभावित मान क्या हैं? / If the roots of \(x^2-2mx+49=0\) are equal, what are the possible values of (m)?

Correct Answer: A. \(m=\pm7\). Explanation: समान मूलों के लिए (D=0) चाहिए। यहाँ ((-2m)2-196=0), इसलिए \(m=\pm7\)। / For equal roots, (D=0) is needed. Here ((-2m)2-196=0), so \(m=\pm7\).

Which concept should I revise for this Mathematics MCQ?

For equal roots, (D=0) is needed. Here ((-2m)2-196=0), so \(m=\pm7\).

What exam hint can help solve this Mathematics question?

समान मूलों के लिए (D=0) चाहिए। यहाँ ((-2m)2-196=0), इसलिए \(m=\pm7\)।

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