यदि \(x^2-2mx+36=0\) के मूल समान हैं, तो (m) के संभावित मान क्या हैं?
If the roots of \(x^2-2mx+36=0\) are equal, what are the possible values of (m)?
Explanation opens after your attempt
Correct Answer
A. \(m=\pm6\)
Concept
For equal roots, (D=0), so ((-2m)2-144=0). This gives \(m^2=36\) and \(m=\pm6\).
Why this answer is correct
The correct answer is A. \(m=\pm6\). For equal roots, (D=0), so ((-2m)2-144=0). This gives \(m^2=36\) and \(m=\pm6\).
Exam Tip
समान मूलों के लिए (D=0), अतः ((-2m)2-144=0) होगा। इससे \(m^2=36\) और \(m=\pm6\) है।
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