यदि \(x^2-16x+q=0\) की जड़ें (5:3) के अनुपात में हैं, तो (q) का मान क्या होगा?
If the roots of \(x^2-16x+q=0\) are in the ratio (5:3), what is the value of (q)?
Explanation opens after your attempt
C. (60)
Concept
Let the roots be (5r) and (3r). From (8r=16), (r=2), so the product is \(15r^2=60\).
Why this answer is correct
The correct answer is C. (60). Let the roots be (5r) and (3r). From (8r=16), (r=2), so the product is \(15r^2=60\).
Exam Tip
जड़ें (5r) और (3r) मानें। (8r=16) से (r=2), इसलिए गुणनफल \(15r^2=60\) है।
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