यदि \(x^2-14x+q=0\) की जड़ें (3:4) के अनुपात में हैं, तो (q) का मान क्या होगा?
If the roots of \(x^2-14x+q=0\) are in the ratio (3:4), what is the value of (q)?
Explanation opens after your attempt
C. (48)
Concept
Let the roots be (3r) and (4r). From (7r=14), (r=2), so the product is \(12r^2=48\).
Why this answer is correct
The correct answer is C. (48). Let the roots be (3r) and (4r). From (7r=14), (r=2), so the product is \(12r^2=48\).
Exam Tip
जड़ें (3r) और (4r) मानें। (7r=14) से (r=2), इसलिए गुणनफल \(12r^2=48\) है।
Login to save your score, XP, coins and progress.