यदि \(x^2-12x+q=0\) की जड़ें (2:3) के अनुपात में हैं, तो (q) का मान क्या होगा?
If the roots of \(x^2-12x+q=0\) are in the ratio (2:3), what is the value of (q)?
Explanation opens after your attempt
Correct Answer
A. \(\frac{864}{25}\)
Concept
Let the roots be (2r) and (3r). From (5r=12), \(r=\frac{12}{5}\), so the product is \(6r^2=\frac{864}{25}\).
Why this answer is correct
The correct answer is A. \(\frac{864}{25}\). Let the roots be (2r) and (3r). From (5r=12), \(r=\frac{12}{5}\), so the product is \(6r^2=\frac{864}{25}\).
Exam Tip
जड़ें (2r) और (3r) मानें। (5r=12) से \(r=\frac{12}{5}\), इसलिए गुणनफल \(6r^2=\frac{864}{25}\) है।
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