यदि \(9x^2-20x+p=0\) के मूलों का गुणनफल \(\frac{1}{3}\) है, तो (p) क्या होगा?
If the product of roots of \(9x^2-20x+p=0\) is \(\frac{1}{3}\), what is (p)?
Explanation opens after your attempt
Correct Answer
A. (3)
Step 1
Concept
The product of roots is \(\frac{p}{9}\), so \(\frac{p}{9}=\frac{1}{3}\) gives (p=3). In exams, use the product formula \(\frac{c}{a}\).
Step 2
Why this answer is correct
The correct answer is A. (3). The product of roots is \(\frac{p}{9}\), so \(\frac{p}{9}=\frac{1}{3}\) gives (p=3). In exams, use the product formula \(\frac{c}{a}\).
Step 3
Exam Tip
मूलों का गुणनफल \(\frac{p}{9}\) है, इसलिए \(\frac{p}{9}=\frac{1}{3}\) से (p=3) है। परीक्षा में गुणनफल का सूत्र \(\frac{c}{a}\) लगाएं।
Mathematics Answer, Explanation and Revision Hints
यदि \(9x^2-20x+p=0\) के मूलों का गुणनफल \(\frac{1}{3}\) है, तो (p) क्या होगा? / If the product of roots of \(9x^2-20x+p=0\) is \(\frac{1}{3}\), what is (p)?
Correct Answer: A. (3). Explanation: मूलों का गुणनफल \(\frac{p}{9}\) है, इसलिए \(\frac{p}{9}=\frac{1}{3}\) से (p=3) है। परीक्षा में गुणनफल का सूत्र \(\frac{c}{a}\) लगाएं। / The product of roots is \(\frac{p}{9}\), so \(\frac{p}{9}=\frac{1}{3}\) gives (p=3). In exams, use the product formula \(\frac{c}{a}\).
Which concept should I revise for this Mathematics MCQ?
The product of roots is \(\frac{p}{9}\), so \(\frac{p}{9}=\frac{1}{3}\) gives (p=3). In exams, use the product formula \(\frac{c}{a}\).
What exam hint can help solve this Mathematics question?
मूलों का गुणनफल \(\frac{p}{9}\) है, इसलिए \(\frac{p}{9}=\frac{1}{3}\) से (p=3) है। परीक्षा में गुणनफल का सूत्र \(\frac{c}{a}\) लगाएं।
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