यदि ग्राफ में दो रेखाओं का प्रतिच्छेद (\left\(-\frac{3}{2},4\right\)) है, तो कौन सा युग्म सही हो सकता है?

If the intersection of two lines on a graph is (\left\(-\frac{3}{2},4\right\)), which pair can be correct?

Explanation opens after your attempt
Correct Answer

A. (2x+y=1), \(x+2y=\frac{13}{2}\)

Step 1

Concept

Substituting (\left\(-\frac{3}{2},4\right\)) makes both (2x+y=1) and \(x+2y=\frac{13}{2}\) true. The intersection point should be checked in both equations.

Step 2

Why this answer is correct

The correct answer is A. (2x+y=1), \(x+2y=\frac{13}{2}\). Substituting (\left\(-\frac{3}{2},4\right\)) makes both (2x+y=1) and \(x+2y=\frac{13}{2}\) true. The intersection point should be checked in both equations.

Step 3

Exam Tip

(\left\(-\frac{3}{2},4\right\)) रखने पर (2x+y=1) और \(x+2y=\frac{13}{2}\) दोनों सत्य हैं। प्रतिच्छेद बिंदु को दोनों समीकरणों में जांचना चाहिए।

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Mathematics Answer, Explanation and Revision Hints

यदि ग्राफ में दो रेखाओं का प्रतिच्छेद (\left\(-\frac{3}{2},4\right\)) है, तो कौन सा युग्म सही हो सकता है? / If the intersection of two lines on a graph is (\left\(-\frac{3}{2},4\right\)), which pair can be correct?

Correct Answer: A. (2x+y=1), \(x+2y=\frac{13}{2}\). Explanation: (\left\(-\frac{3}{2},4\right\)) रखने पर (2x+y=1) और \(x+2y=\frac{13}{2}\) दोनों सत्य हैं। प्रतिच्छेद बिंदु को दोनों समीकरणों में जांचना चाहिए। / Substituting (\left\(-\frac{3}{2},4\right\)) makes both (2x+y=1) and \(x+2y=\frac{13}{2}\) true. The intersection point should be checked in both equations.

Which concept should I revise for this Mathematics MCQ?

Substituting (\left\(-\frac{3}{2},4\right\)) makes both (2x+y=1) and \(x+2y=\frac{13}{2}\) true. The intersection point should be checked in both equations.

What exam hint can help solve this Mathematics question?

(\left\(-\frac{3}{2},4\right\)) रखने पर (2x+y=1) और \(x+2y=\frac{13}{2}\) दोनों सत्य हैं। प्रतिच्छेद बिंदु को दोनों समीकरणों में जांचना चाहिए।

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