यदि (p(x)=x+2) का ग्राफ (x)-अक्ष को काटता है, तो शून्यक कौन-सा है?
If the graph of (p(x)=x+2) cuts the (x)-axis, which is the zero?
Explanation opens after your attempt
B. (-2)
Concept
For the zero, (x+2=0), so (x=-2). The graph cuts the (x)-axis at (x=-2).
Why this answer is correct
The correct answer is B. (-2). For the zero, (x+2=0), so (x=-2). The graph cuts the (x)-axis at (x=-2).
Exam Tip
शून्यक के लिए (x+2=0), इसलिए (x=-2)। ग्राफ (x)-अक्ष को (x=-2) पर काटेगा।
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