यदि (x-2-2(k+3)x+k-2-16=0) के समान मूलों के लिए सही (k) चाहिए, तो कौनसा मान सही है?
If the correct (k) is needed for equal roots of (x-2-2(k+3)x+k-2-16=0), which value is correct?
Explanation opens after your attempt
Correct Answer
B. \(k=-\frac{25}{6}\)
Concept
(D=4(k+3)2-4\(k^2-16\)=0) gives ((k+3)2=k-2-16), so (6k+25=0) and \(k=-\frac{25}{6}\). In exams, handle the constant term carefully after expansion.
Why this answer is correct
The correct answer is B. \(k=-\frac{25}{6}\). (D=4(k+3)2-4\(k^2-16\)=0) gives ((k+3)2=k-2-16), so (6k+25=0) and \(k=-\frac{25}{6}\). In exams, handle the constant term carefully after expansion.
Exam Tip
(D=4(k+3)2-4\(k^2-16\)=0) से ((k+3)2=k-2-16), इसलिए (6k+25=0) और \(k=-\frac{25}{6}\) है। परीक्षा में विस्तार के बाद स्थिर पद ध्यान से जोड़ें।
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