यदि \(\sqrt{x}=x^{\frac{1}{2}}\) और (x>0), तो \(\sqrt{x^{3}}\cdot x^{-\frac{1}{2}}\) किसके बराबर है?
If \(\sqrt{x}=x^{\frac{1}{2}}\) and (x>0), then \(\sqrt{x^{3}}\cdot x^{-\frac{1}{2}}\) equals which expression?
Explanation opens after your attempt
Correct Answer
A. (x)
Concept
Since \(\sqrt{x^{3}}=x^{\frac{3}{2}}\), \(x^{\frac{3}{2}}\cdot x^{-\frac{1}{2}}=x^{1}=x\). In exams, convert radicals to fractional exponents.
Why this answer is correct
The correct answer is A. (x). Since \(\sqrt{x^{3}}=x^{\frac{3}{2}}\), \(x^{\frac{3}{2}}\cdot x^{-\frac{1}{2}}=x^{1}=x\). In exams, convert radicals to fractional exponents.
Exam Tip
\(\sqrt{x^{3}}=x^{\frac{3}{2}}\), इसलिए \(x^{\frac{3}{2}}\cdot x^{-\frac{1}{2}}=x^{1}=x\)। परीक्षा में मूल को भिन्न घात में बदलें।
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