Hard Mathematics Polynomials Class 10 Level 27

यदि \(\sqrt{2}\) और \(\sqrt{3}\) किसी द्विघात बहुपद के शून्यक हैं, तो उस बहुपद के गुणांक किस प्रकार होंगे?

If \(\sqrt{2}\) and \(\sqrt{3}\) are zeroes of a quadratic polynomial, what type of coefficients will that polynomial have?

Explanation opens after your attempt
Correct Answer

B. कम से कम एक गुणांक अपरिमेय होगाAt least one coefficient will be irrational

Step 1

Concept

The sum \(\sqrt{2}+\sqrt{3}\) is irrational, so the coefficient of (x) in the monic polynomial is irrational. For rational coefficients, such zeroes must occur as conjugates.

Step 2

Why this answer is correct

The correct answer is B. कम से कम एक गुणांक अपरिमेय होगा / At least one coefficient will be irrational. The sum \(\sqrt{2}+\sqrt{3}\) is irrational, so the coefficient of (x) in the monic polynomial is irrational. For rational coefficients, such zeroes must occur as conjugates.

Step 3

Exam Tip

योग \(\sqrt{2}+\sqrt{3}\) अपरिमेय है, इसलिए एकक बहुपद में (x) का गुणांक अपरिमेय होगा। परिमेय गुणांक के लिए ऐसे शून्यक संयुग्मी रूप में होने चाहिए।

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Mathematics Answer, Explanation and Revision Hints

यदि \(\sqrt{2}\) और \(\sqrt{3}\) किसी द्विघात बहुपद के शून्यक हैं, तो उस बहुपद के गुणांक किस प्रकार होंगे? / If \(\sqrt{2}\) and \(\sqrt{3}\) are zeroes of a quadratic polynomial, what type of coefficients will that polynomial have?

Correct Answer: B. कम से कम एक गुणांक अपरिमेय होगा / At least one coefficient will be irrational. Explanation: योग \(\sqrt{2}+\sqrt{3}\) अपरिमेय है, इसलिए एकक बहुपद में (x) का गुणांक अपरिमेय होगा। परिमेय गुणांक के लिए ऐसे शून्यक संयुग्मी रूप में होने चाहिए। / The sum \(\sqrt{2}+\sqrt{3}\) is irrational, so the coefficient of (x) in the monic polynomial is irrational. For rational coefficients, such zeroes must occur as conjugates.

Which concept should I revise for this Mathematics MCQ?

The sum \(\sqrt{2}+\sqrt{3}\) is irrational, so the coefficient of (x) in the monic polynomial is irrational. For rational coefficients, such zeroes must occur as conjugates.

What exam hint can help solve this Mathematics question?

योग \(\sqrt{2}+\sqrt{3}\) अपरिमेय है, इसलिए एकक बहुपद में (x) का गुणांक अपरिमेय होगा। परिमेय गुणांक के लिए ऐसे शून्यक संयुग्मी रूप में होने चाहिए।

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