Hard Mathematics Quadratic Equations Class 10 Level 32

यदि \(x^2+px+18=0\) के मूलों का अनुपात (1:2) है और दोनों ऋणात्मक हैं तो (p) क्या होगा?

If roots of \(x^2+px+18=0\) are in the ratio (1:2) and both are negative, what is (p)?

Explanation opens after your attempt
Correct Answer

A. (9)

Step 1

Concept

The roots are (-3) and (-6) because the product is (18). Their sum is (-9), so (p=9).

Step 2

Why this answer is correct

The correct answer is A. (9). The roots are (-3) and (-6) because the product is (18). Their sum is (-9), so (p=9).

Step 3

Exam Tip

मूल (-3) और (-6) होंगे क्योंकि गुणनफल (18) है। उनका योग (-9) है इसलिए (p=9) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2+px+18=0\) के मूलों का अनुपात (1:2) है और दोनों ऋणात्मक हैं तो (p) क्या होगा? / If roots of \(x^2+px+18=0\) are in the ratio (1:2) and both are negative, what is (p)?

Correct Answer: A. (9). Explanation: मूल (-3) और (-6) होंगे क्योंकि गुणनफल (18) है। उनका योग (-9) है इसलिए (p=9) है। / The roots are (-3) and (-6) because the product is (18). Their sum is (-9), so (p=9).

Which concept should I revise for this Mathematics MCQ?

The roots are (-3) and (-6) because the product is (18). Their sum is (-9), so (p=9).

What exam hint can help solve this Mathematics question?

मूल (-3) और (-6) होंगे क्योंकि गुणनफल (18) है। उनका योग (-9) है इसलिए (p=9) है।

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